What is (6x^4-12x^3+6x^2)/(3x^2) ?

The solution to (6x^4-12x^3+6x^2)/(3x^2) is 2(x-1)^2

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simplify (6x^4-12x^3+6x^2)/(3x^2)

simplify

\frac{6 x ^{4} - 12 x ^{3} + 6 x ^{2}}{3 x ^{2}}

2 (x - 1)^{2}

Solution steps

\frac{6 x ^{4} - 12 x ^{3} + 6 x ^{2}}{3 x ^{2}}

Factor

6 x^{4} - 12 x^{3} + 6 x^{2} : 6 x^{2} (x - 1)^{2}

= \frac{6 x ^{2} ( x - 1 ) ^{2}}{3 x ^{2}}

Cancel the common factor:

x^{2}

= \frac{6 ( x - 1 ) ^{2}}{3}

Divide the numbers:

\frac{6}{3} = 2

= 2 (x - 1)^{2}

- \frac{1}{4} + \frac{3}{2}

p (x - 3 y) + (x - 2 p) (x - 3 y)

9^{2} - x

(2 - 1) (2 + 1)

(2 n + 2) (2 n - 2)

What is (6x^4-12x^3+6x^2)/(3x^2) ?
The solution to (6x^4-12x^3+6x^2)/(3x^2) is 2(x-1)^2