What is (a^3b^{-5}c^{-1})/(c^{-4)ba^{-4}} ?

The solution to (a^3b^{-5}c^{-1})/(c^{-4)ba^{-4}} is (a^7c^3)/(b^6)

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simplify (a^3b^{-5}c^{-1})/(c^{-4)ba^{-4}}

simplify

\frac{a ^{3} b ^{- 5} c ^{- 1}}{c ^{- 4} b a ^{- 4}}

\frac{a ^{7} c ^{3}}{b ^{6}}

Solution steps

\frac{a ^{3} b ^{- 5} c ^{- 1}}{c ^{- 4} b a ^{- 4}}

Simplify

\frac{a ^{3}}{a ^{- 4}} : a^{7}

= \frac{a ^{7} b ^{- 5} c ^{- 1}}{c ^{- 4} b}

Simplify

\frac{c ^{- 1}}{c ^{- 4}} : c^{3}

= \frac{a ^{7} b ^{- 5} c ^{3}}{b}

Simplify

\frac{b ^{- 5}}{b} : \frac{1}{b ^{6}}

= \frac{a ^{7} c ^{3}}{b ^{6}}

\frac{2}{6} + \frac{1}{7}

x^{3} + 4 x^{2} + 6 x + 4

(5 x + 8) (5 x - 8)

e^{e^{1}}

3 - 2 x + 4 - x^{5} + 2 x

What is (a^3b^{-5}c^{-1})/(c^{-4)ba^{-4}} ?
The solution to (a^3b^{-5}c^{-1})/(c^{-4)ba^{-4}} is (a^7c^3)/(b^6)