What is sqrt(4x^2+4y^2) ?

The solution to sqrt(4x^2+4y^2) is 2sqrt(x^2+y^2)

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simplify sqrt(4x^2+4y^2)

simplify

4 x^{2} + 4 y^{2}

2 x^{2} + y^{2}

Solution steps

4 x^{2} + 4 y^{2}

Factor out common term

4

= 4 (x^{2} + y^{2})

Apply radical rule:

ab = a b,

assuming

a \geq 0, b \geq 0

4 (x^{2} + y^{2}) = 4 x^{2} + y^{2}

= 4 x^{2} + y^{2}

4 = 2

= 2 x^{2} + y^{2}

72 \div 18

545 - 880 + 420 + 25

4 \frac{2}{9} + 2 \frac{1}{6}

\frac{x ^{2}}{2} - 2 x

(- 5 a^{2})^{3} \cdot a^{5}