What is expand 3x^5(2x^2+4x+1) ?

The solution to expand 3x^5(2x^2+4x+1) is 6x^7+12x^6+3x^5

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expand 3x^5(2x^2+4x+1)

expand

3 x^{5} (2 x^{2} + 4 x + 1)

6 x^{7} + 12 x^{6} + 3 x^{5}

Solution steps

3 x^{5} (2 x^{2} + 4 x + 1)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

3 x^{5} (2 x^{2} + 4 x + 1) = 3 x^{5} \cdot 2 x^{2} + 3 x^{5} \cdot 4 x + 3 x^{5} \cdot 1

= 3 x^{5} \cdot 2 x^{2} + 3 x^{5} \cdot 4 x + 3 x^{5} \cdot 1

Simplify

3 x^{5} \cdot 2 x^{2} + 3 x^{5} \cdot 4 x + 3 x^{5} \cdot 1 : 6 x^{7} + 12 x^{6} + 3 x^{5}

= 6 x^{7} + 12 x^{6} + 3 x^{5}

\frac{3}{5} \div \frac{3}{10}

\frac{2 π}{3.14}

\frac{20 z ^{6}}{16 z ^{7}}

\frac{2 ( n ^{3} ) ^{4}}{6 n ^{6}}

\frac{18}{162}

What is expand 3x^5(2x^2+4x+1) ?
The solution to expand 3x^5(2x^2+4x+1) is 6x^7+12x^6+3x^5