What is sqrt(36)+(3^4+5*7)+sqrt(4)*9-(2^3-7) ?

The solution to sqrt(36)+(3^4+5*7)+sqrt(4)*9-(2^3-7) is 139

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simplify sqrt(36)+(3^4+57)+sqrt(4)9-(2^3-7)

simplify

36 + (3^{4} + 5 \cdot 7) + 4 \cdot 9 - (2^{3} - 7)

139

Solution steps

36 + (3^{4} + 5 \cdot 7) + 4 \cdot 9 - (2^{3} - 7)

Apply rule:

a + (b + c) = a + b + c

36 + (3^{4} + 5 \cdot 7) = 36 + 3^{4} + 5 \cdot 7

= 36 + 3^{4} + 5 \cdot 7 + 4 \cdot 9 - (2^{3} - 7)

36 = 6

3^{4} = 81

5 \cdot 7 = 35

4 \cdot 9 = 18

2^{3} - 7 = 1

= 6 + 81 + 35 + 18 - 1

Add the numbers:

6 + 81 + 35 + 18 - 1 = 139

= 139

\frac{\frac{18 x ^{2}}{x - 1}}{\frac{x}{2 x - 2}}

\frac{x ^{2} + x - 2}{x ^{2} - 1}

\frac{22}{33}

11 \cdot 6

\frac{a ^{\frac{3}{2}} \cdot a ^{\frac{5}{2}}}{2 a ^{3}}

What is sqrt(36)+(3^4+5*7)+sqrt(4)*9-(2^3-7) ?
The solution to sqrt(36)+(3^4+5*7)+sqrt(4)*9-(2^3-7) is 139