What is 7/(3s+6)*(s+2)/(21) ?

The solution to 7/(3s+6)*(s+2)/(21) is 1/9

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simplify 7/(3s+6)*(s+2)/(21)

simplify

\frac{7}{3 s + 6} \cdot \frac{s + 2}{21}

\frac{1}{9}

Decimal Notation

0.11111 \dots

Solution steps

\frac{7}{3 s + 6} \cdot \frac{s + 2}{21}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{7 ( s + 2 )}{( 3 s + 6 ) \cdot 21}

Factor the number:

21 = 7 \cdot 3

= \frac{7 ( s + 2 )}{( 3 s + 6 ) \cdot 7 \cdot 3}

Cancel the common factor:

7

= \frac{s + 2}{( 3 s + 6 ) \cdot 3}

Factor

3 s + 6 : 3 (s + 2)

= \frac{s + 2}{3 ( s + 2 ) \cdot 3}

Cancel the common factor:

s + 2

= \frac{1}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{1}{9}

\frac{51}{17}

\frac{n ^{4}}{n ^{6}}

6 + 12

(3 x^{2} - 2 x + 6) + (x^{2} + 2 x + 1)

\frac{4 + 4 i}{1 + 3 i}