What is (3x^2-x-7)-(5x^2-4x-2)+(x+3)(x+2) ?

The solution to (3x^2-x-7)-(5x^2-4x-2)+(x+3)(x+2) is -x^2+8x+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (3x^2-x-7)-(5x^2-4x-2)+(x+3)(x+2)

simplify

(3 x^{2} - x - 7) - (5 x^{2} - 4 x - 2) + (x + 3) (x + 2)

- x^{2} + 8 x + 1

Solution steps

(3 x^{2} - x - 7) - (5 x^{2} - 4 x - 2) + (x + 3) (x + 2)

Apply rule:

(a) = a

(3 x^{2} - x - 7) = 3 x^{2} - x - 7

= 3 x^{2} - x - 7 - (5 x^{2} - 4 x - 2) + (x + 3) (x + 2)

Apply the distributive law:

- (a - b) = - a + b

- (5 x^{2} - 4 x - 2) = - 5 x^{2} + 4 x + 2

= 3 x^{2} - x - 7 - 5 x^{2} + 4 x + 2 + (x + 3) (x + 2)

Expand

(x + 3) (x + 2) : x^{2} + 5 x + 6

= 3 x^{2} - x - 7 - 5 x^{2} + 4 x + 2 + x^{2} + 5 x + 6

Group like terms

= 3 x^{2} - 5 x^{2} + x^{2} - x + 4 x + 5 x - 7 + 2 + 6

Add similar elements:

3 x^{2} - 5 x^{2} + x^{2} = - x^{2}

= - x^{2} - x + 4 x + 5 x - 7 + 2 + 6

Add similar elements:

- x + 4 x + 5 x = 8 x

= - x^{2} + 8 x - 7 + 2 + 6

Add the numbers:

- 7 + 2 + 6 = 1

= - x^{2} + 8 x + 1

\frac{4}{5} + \frac{3}{2}

96 \cdot 3

19 \cdot 9

7 \cdot 30

\frac{1}{5} \div \frac{1}{10}

What is (3x^2-x-7)-(5x^2-4x-2)+(x+3)(x+2) ?
The solution to (3x^2-x-7)-(5x^2-4x-2)+(x+3)(x+2) is -x^2+8x+1