What is ((1/6+3/7))/((2/3)^2+1/5-1) ?

The solution to ((1/6+3/7))/((2/3)^2+1/5-1) is -375/224

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simplify ((1/6+3/7))/((2/3)^2+1/5-1)

simplify

\frac{( \frac{1}{6} + \frac{3}{7} )}{( \frac{2}{3} ) ^{2} + \frac{1}{5} - 1}

- \frac{375}{224}

Decimal Notation

- 1.67410 \dots

Solution steps

\frac{\frac{1}{6} + \frac{3}{7}}{( \frac{2}{3} ) ^{2} + \frac{1}{5} - 1}

\frac{1}{6} + \frac{3}{7} = \frac{25}{42}

= \frac{\frac{25}{42}}{( \frac{2}{3} ) ^{2} + \frac{1}{5} - 1}

(\frac{2}{3})^{2} + \frac{1}{5} - 1 = - \frac{16}{45}

= \frac{\frac{25}{42}}{- \frac{16}{45}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{\frac{25}{42}}{\frac{16}{45}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

\frac{\frac{25}{42}}{\frac{16}{45}} = \frac{25 \cdot 45}{42 \cdot 16}

= - \frac{25 \cdot 45}{42 \cdot 16}

Cancel

- \frac{25 \cdot 45}{42 \cdot 16} : - \frac{375}{224}

= - \frac{375}{224}

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What is ((1/6+3/7))/((2/3)^2+1/5-1) ?
The solution to ((1/6+3/7))/((2/3)^2+1/5-1) is -375/224