What is expand (x^3+1)(x^3-1) ?

The solution to expand (x^3+1)(x^3-1) is x^6-1

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expand (x^3+1)(x^3-1)

expand

(x^{3} + 1) (x^{3} - 1)

x^{6} - 1

Solution steps

(x^{3} + 1) (x^{3} - 1)

Apply Difference of Two Squares

(x^{3} + 1) (x^{3} - 1) : x^{6} - 1

= x^{6} - 1

2 x^{2} yz - 4 x y z^{2} + 8 x y^{2} z^{3}

(5 x^{2} + 5 x + 7) (8 x + 6)

27 + 12 - 75

(k + 4)^{2}

\frac{26}{4 + 3}