What are the solutions to the equation 4x^2+5x+13/8 =0 ?

The solutions to the equation 4x^2+5x+13/8 =0 are x=-5/8+i 1/8 ,x=-5/8-i 1/8

Find the zeros of 4x^2+5x+13/8 =0

The zeros of 4x^2+5x+13/8 =0 are x=-5/8+i 1/8 ,x=-5/8-i 1/8

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4 x^{2} + 5 x + \frac{13}{8} = 0

x = - \frac{5}{8} + i \frac{1}{8}, x = - \frac{5}{8} - i \frac{1}{8}

Solution steps

4 x^{2} + 5 x + \frac{13}{8} = 0

Multiply both sides by

8

32 x^{2} + 40 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 32 \cdot 13}{2 \cdot 32}

Simplify

4 0^{2} - 4 \cdot 32 \cdot 13 : 8 i

x_{1, 2} = \frac{- 40 \pm 8 i}{2 \cdot 32}

Separate the solutions

x_{1} = \frac{- 40 + 8 i}{2 \cdot 32}, x_{2} = \frac{- 40 - 8 i}{2 \cdot 32}

x = \frac{- 40 + 8 i}{2 \cdot 32} : - \frac{5}{8} + i \frac{1}{8}

x = \frac{- 40 - 8 i}{2 \cdot 32} : - \frac{5}{8} - i \frac{1}{8}

The solutions to the quadratic equation are:

x = - \frac{5}{8} + i \frac{1}{8}, x = - \frac{5}{8} - i \frac{1}{8}

6 x < - 10

32 (56 - 73)

x^{3} - 4 x^{2}

1 = 7 + 2 (7 a - 3)

6 4^{- \frac{1}{2}}

What are the solutions to the equation 4x^2+5x+13/8 =0 ?
The solutions to the equation 4x^2+5x+13/8 =0 are x=-5/8+i 1/8 ,x=-5/8-i 1/8
Find the zeros of 4x^2+5x+13/8 =0
The zeros of 4x^2+5x+13/8 =0 are x=-5/8+i 1/8 ,x=-5/8-i 1/8