What is (x+2)(x^2-2x+4)+(x-2)(x^2+2x+4) ?

The solution to (x+2)(x^2-2x+4)+(x-2)(x^2+2x+4) is 2x^3

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simplify (x+2)(x^2-2x+4)+(x-2)(x^2+2x+4)

simplify

(x + 2) (x^{2} - 2 x + 4) + (x - 2) (x^{2} + 2 x + 4)

2 x^{3}

Solution steps

(x + 2) (x^{2} - 2 x + 4) + (x - 2) (x^{2} + 2 x + 4)

Expand

(x + 2) (x^{2} - 2 x + 4) : x^{3} + 8

= x^{3} + 8 + (x - 2) (x^{2} + 2 x + 4)

Expand

(x - 2) (x^{2} + 2 x + 4) : x^{3} - 8

= x^{3} + 8 + x^{3} - 8

Group like terms

= x^{3} + x^{3} + 8 - 8

Add similar elements:

x^{3} + x^{3} = 2 x^{3}

= 2 x^{3} + 8 - 8

Subtract the numbers:

8 - 8 = 0

= 2 x^{3}

\frac{8}{4}

\frac{3 x ^{3}}{x ^{3}}

\frac{81}{27}

4 y (6 - q) + 6 (6 - q)

m - \frac{m}{2} + \frac{2 m}{3} - \frac{m}{4}

What is (x+2)(x^2-2x+4)+(x-2)(x^2+2x+4) ?
The solution to (x+2)(x^2-2x+4)+(x-2)(x^2+2x+4) is 2x^3