What is 3\sqrt[3]{-27y^{-6}x^9} ?

The solution to 3\sqrt[3]{-27y^{-6}x^9} is -(9x^3)/(y^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 3\sqrt[3]{-27y^{-6}x^9}

simplify

- \frac{9 x ^{3}}{y ^{2}}

Solution steps

Apply radical rule:

assuming

a \geq 0, b \geq 0

Apply radical rule:

assuming

a \geq 0, b \geq 0

Simplify

= 3 \cdot 3 \cdot \frac{1}{y ^{2}} (- x^{3})

Apply rule:

a (- b) = - ab

3 \cdot 3 \cdot \frac{1}{y ^{2}} (- x^{3}) = - 3 \cdot 3 \cdot \frac{1}{y ^{2}} x^{3}

= - 3 \cdot 3 \cdot \frac{1}{y ^{2}} x^{3}

Multiply the numbers:

- 3 \cdot 3 = - 9

= - 9 \cdot \frac{1}{y ^{2}} x^{3}

= - 9 x^{3} \frac{1}{y ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{9 x ^{3} \cdot 1}{y ^{2}}

Multiply the numbers:

9 \cdot 1 = 9

= - \frac{9 x ^{3}}{y ^{2}}

m x^{2 m + 3} + 3 x^{m + 5}

\frac{2 ^{100}}{2}

6 \div \frac{3}{2}

\frac{x ^{2} - 1}{x ^{4} - 1}

(7 y^{6})^{2} (2 y^{8})^{4}

What is 3\sqrt[3]{-27y^{-6}x^9} ?
The solution to 3\sqrt[3]{-27y^{-6}x^9} is -(9x^3)/(y^2)