What are the solutions to the equation 6-2x-x^2=x+6 ?

The solutions to the equation 6-2x-x^2=x+6 are x=-3,x=0

Find the zeros of 6-2x-x^2=x+6

The zeros of 6-2x-x^2=x+6 are x=-3,x=0

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6 - 2 x - x^{2} = x + 6

x = - 3, x = 0

Solution steps

6 - 2 x - x^{2} = x + 6

Move

6

to the left side

- x^{2} - 2 x = x

Move

x

to the left side

- x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 3}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 3}{2 ( - 1 )} : - 3

x = \frac{- ( - 3 ) - 3}{2 ( - 1 )} : 0

The solutions to the quadratic equation are:

x = - 3, x = 0

2 x^{2} - 4 < 0

x^{2} + 4 x = - 5

9 e = 45

\frac{27 x ^{6} y ^{3}}{9 x ^{4} y ^{5}}

- x^{2} + 3 x - 2 < 0

What are the solutions to the equation 6-2x-x^2=x+6 ?
The solutions to the equation 6-2x-x^2=x+6 are x=-3,x=0
Find the zeros of 6-2x-x^2=x+6
The zeros of 6-2x-x^2=x+6 are x=-3,x=0