What is factor 3x^3-4x^2+4x-1 ?

The solution to factor 3x^3-4x^2+4x-1 is (3x-1)(x^2-x+1)

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factor 3x^3-4x^2+4x-1

factor

3 x^{3} - 4 x^{2} + 4 x - 1

(3 x - 1) (x^{2} - x + 1)

Solution steps

3 x^{3} - 4 x^{2} + 4 x - 1

Use the rational root theorem

a_{0} = 1, a_{n} = 3

The dividers of

a_{0} : 1,

The dividers of

a_{n} : 1, 3

Therefore, check the following rational numbers:

\pm \frac{1}{1 , 3}

\frac{1}{3}

is a root of the expression, so factor out

3 x - 1

= (3 x - 1) \frac{3 x ^{3} - 4 x ^{2} + 4 x - 1}{3 x - 1}

\frac{3 x ^{3} - 4 x ^{2} + 4 x - 1}{3 x - 1} = x^{2} - x + 1

= (3 x - 1) (x^{2} - x + 1)

8 1^{8^{- 9^{- 2^{- 1}}}}

\frac{1}{2} lo g_{2} (\frac{1}{2}) + \frac{1}{2} lo g_{2} (\frac{1}{2})

s + \frac{1}{s}

9 x^{2} + 6 x - 12

(3 x - 4)^{5}

What is factor 3x^3-4x^2+4x-1 ?
The solution to factor 3x^3-4x^2+4x-1 is (3x-1)(x^2-x+1)