What are the solutions to the equation x^2+5x-5=0 ?

The solutions to the equation x^2+5x-5=0 are x=(-5+3sqrt(5))/2 ,x=(-5-3sqrt(5))/2

Find the zeros of x^2+5x-5=0

The zeros of x^2+5x-5=0 are x=(-5+3sqrt(5))/2 ,x=(-5-3sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 5 x - 5 = 0

x = \frac{- 5 + 3 5}{2}, x = \frac{- 5 - 3 5}{2}

Solution steps

x^{2} + 5 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 5) = 35

x_{1, 2} = \frac{- 5 \pm 3 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 3 5}{2 \cdot 1}, x_{2} = \frac{- 5 - 3 5}{2 \cdot 1}

x = \frac{- 5 + 3 5}{2 \cdot 1} : \frac{- 5 + 3 5}{2}

x = \frac{- 5 - 3 5}{2 \cdot 1} : \frac{- 5 - 3 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 3 5}{2}, x = \frac{- 5 - 3 5}{2}

1.76 = \frac{x - 693366}{693366} \cdot 100

x^{2} - x - \frac{5}{2} = 0

- 4.8 x^{2} + 1.6 x + 24 = 0

5^{2 x} - 5^{x + 1} + 5 \geq 5^{x + 1} - 20

What are the solutions to the equation x^2+5x-5=0 ?
The solutions to the equation x^2+5x-5=0 are x=(-5+3sqrt(5))/2 ,x=(-5-3sqrt(5))/2
Find the zeros of x^2+5x-5=0
The zeros of x^2+5x-5=0 are x=(-5+3sqrt(5))/2 ,x=(-5-3sqrt(5))/2