What is expand (4x^2+7x)(5x^2-3x) ?

The solution to expand (4x^2+7x)(5x^2-3x) is 20x^4+23x^3-21x^2

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expand (4x^2+7x)(5x^2-3x)

expand

(4 x^{2} + 7 x) (5 x^{2} - 3 x)

20 x^{4} + 23 x^{3} - 21 x^{2}

Solution steps

(4 x^{2} + 7 x) (5 x^{2} - 3 x)

Apply FOIL method

(4 x^{2} + 7 x) (5 x^{2} - 3 x) : 20 x^{4} + 23 x^{3} - 21 x^{2}

= 20 x^{4} + 23 x^{3} - 21 x^{2}

\frac{2}{3 3}

\frac{3}{7} \cdot \frac{1}{2}

(a + b)^{2} - 4 ab

1 - sec^{2} (x) + tan^{2} (x) sec^{2} (x)

0 \cdot \frac{1}{2}

What is expand (4x^2+7x)(5x^2-3x) ?
The solution to expand (4x^2+7x)(5x^2-3x) is 20x^4+23x^3-21x^2