What is (x^2-5x+4)/(x^2-x-12) ?

The solution to (x^2-5x+4)/(x^2-x-12) is (x-1)/(x+3)

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simplify (x^2-5x+4)/(x^2-x-12)

simplify

\frac{x ^{2} - 5 x + 4}{x ^{2} - x - 12}

\frac{x - 1}{x + 3}

Solution steps

\frac{x ^{2} - 5 x + 4}{x ^{2} - x - 12}

Factor

x^{2} - 5 x + 4 : (x - 1) (x - 4)

= \frac{( x - 1 ) ( x - 4 )}{x ^{2} - x - 12}

Factor

x^{2} - x - 12 : (x + 3) (x - 4)

= \frac{( x - 1 ) ( x - 4 )}{( x + 3 ) ( x - 4 )}

Cancel the common factor:

x - 4

= \frac{x - 1}{x + 3}

(15 - x)^{2}

\frac{15000}{4 π \cdot ( 7.5 \cdot 1 0 ^{- 3} ) ^{2}}

1 - 1

(\frac{1}{2} 2)^{2}

\frac{12}{4}

What is (x^2-5x+4)/(x^2-x-12) ?
The solution to (x^2-5x+4)/(x^2-x-12) is (x-1)/(x+3)