What is (x^2+10x+16)/(2x^2+4x) ?

The solution to (x^2+10x+16)/(2x^2+4x) is (x+8)/(2x)

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simplify (x^2+10x+16)/(2x^2+4x)

simplify

\frac{x ^{2} + 10 x + 16}{2 x ^{2} + 4 x}

\frac{x + 8}{2 x}

Solution steps

\frac{x ^{2} + 10 x + 16}{2 x ^{2} + 4 x}

Factor

x^{2} + 10 x + 16 : (x + 2) (x + 8)

= \frac{( x + 2 ) ( x + 8 )}{2 x ^{2} + 4 x}

Factor

2 x^{2} + 4 x : 2 x (x + 2)

= \frac{( x + 2 ) ( x + 8 )}{2 x ( x + 2 )}

Cancel the common factor:

x + 2

= \frac{x + 8}{2 x}

(11 m^{15} n^{12})^{2}

p^{2} - 8 p - 20

(8 x^{4} + 1) 2

What is (x^2+10x+16)/(2x^2+4x) ?
The solution to (x^2+10x+16)/(2x^2+4x) is (x+8)/(2x)