What is (x^2-9)/(2x^2-3x-9) ?

The solution to (x^2-9)/(2x^2-3x-9) is (x+3)/(2x+3)

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simplify (x^2-9)/(2x^2-3x-9)

simplify

\frac{x ^{2} - 9}{2 x ^{2} - 3 x - 9}

\frac{x + 3}{2 x + 3}

Solution steps

\frac{x ^{2} - 9}{2 x ^{2} - 3 x - 9}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{2 x ^{2} - 3 x - 9}

Factor

2 x^{2} - 3 x - 9 : (2 x + 3) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{( 2 x + 3 ) ( x - 3 )}

Cancel the common factor:

x - 3

= \frac{x + 3}{2 x + 3}

49 \frac{3}{2}

(x^{2}) 3

98 \cdot 2

(- 2 sin (x))^{2} + (2 cos (x))^{2}

What is (x^2-9)/(2x^2-3x-9) ?
The solution to (x^2-9)/(2x^2-3x-9) is (x+3)/(2x+3)