What is 7x^{-2}y(-3x^4+2y^{-2}) ?

The solution to 7x^{-2}y(-3x^4+2y^{-2}) is (7(-3x^4y^2+2))/(yx^2)

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simplify 7x^{-2}y(-3x^4+2y^{-2})

simplify

7 x^{- 2} y (- 3 x^{4} + 2 y^{- 2})

\frac{7 ( - 3 x ^{4} y ^{2} + 2 )}{y x ^{2}}

Solution steps

7 x^{- 2} y (- 3 x^{4} + 2 y^{- 2})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 2} = \frac{1}{x ^{2}}

= 7 \cdot \frac{1}{x ^{2}} y (- 3 x^{4} + 2 y^{- 2})

Simplify

- 3 x^{4} + 2 y^{- 2} : - 3 x^{4} + \frac{2}{y ^{2}}

= 7 \cdot \frac{1}{x ^{2}} y (- 3 x^{4} + \frac{2}{y ^{2}})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{7 \cdot 1 \cdot y ( - 3 x ^{4} + \frac{2}{y ^{2}} )}{x ^{2}}

Simplify

7 \cdot 1 \cdot y (- 3 x^{4} + \frac{2}{y ^{2}}) : \frac{7 ( - 3 x ^{4} y ^{2} + 2 )}{y}

= \frac{\frac{7 ( - 3 x ^{4} y ^{2} + 2 )}{y}}{x ^{2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{7 ( - 3 x ^{4} y ^{2} + 2 )}{y x ^{2}}

\frac{296 u ^{5} y ^{3}}{242 u ^{2} y ^{5}}

\frac{2 ( a ^{- 1} ) ^{3}}{- 10 a ^{5}}

3 (a + b)

\frac{26}{60}

x + \frac{2}{3}

What is 7x^{-2}y(-3x^4+2y^{-2}) ?
The solution to 7x^{-2}y(-3x^4+2y^{-2}) is (7(-3x^4y^2+2))/(yx^2)