What is (2m-5)(2m-3)-(m^2+5m) ?

The solution to (2m-5)(2m-3)-(m^2+5m) is 3m^2-21m+15

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simplify (2m-5)(2m-3)-(m^2+5m)

simplify

(2 m - 5) (2 m - 3) - (m^{2} + 5 m)

3 m^{2} - 21 m + 15

Solution steps

(2 m - 5) (2 m - 3) - (m^{2} + 5 m)

Apply the distributive law:

- (a + b) = - a - b

- (m^{2} + 5 m) = - m^{2} - 5 m

= (2 m - 5) (2 m - 3) - m^{2} - 5 m

Expand

(2 m - 5) (2 m - 3) : 4 m^{2} - 16 m + 15

= 4 m^{2} - 16 m + 15 - m^{2} - 5 m

Group like terms

= 4 m^{2} - m^{2} - 16 m - 5 m + 15

Add similar elements:

4 m^{2} - m^{2} = 3 m^{2}

= 3 m^{2} - 16 m - 5 m + 15

Add similar elements:

- 16 m - 5 m = - 21 m

= 3 m^{2} - 21 m + 15

2 x^{3} + 2 x^{3}

\frac{5}{12} + \frac{7}{18} - \frac{1}{6} + \frac{4}{9}

62 5^{2}

2 5^{- 0.5}

(4^{4} 6^{- 9}) (4^{- 2} 6^{10})

What is (2m-5)(2m-3)-(m^2+5m) ?
The solution to (2m-5)(2m-3)-(m^2+5m) is 3m^2-21m+15