What is (\frac{8k)/(24k^2-40k)}{1/(15k-25)} ?

The solution to (\frac{8k)/(24k^2-40k)}{1/(15k-25)} is 5

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simplify (\frac{8k)/(24k^2-40k)}{1/(15k-25)}

simplify

\frac{\frac{8 k}{24 k ^{2} - 40 k}}{\frac{1}{15 k - 25}}

5

Solution steps

\frac{\frac{8 k}{24 k ^{2} - 40 k}}{\frac{1}{15 k - 25}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{8 k ( 15 k - 25 )}{( 24 k ^{2} - 40 k ) \cdot 1}

Apply rule:

a \cdot 1 = a

= \frac{8 k ( 15 k - 25 )}{24 k ^{2} - 40 k}

Cancel

\frac{8 k ( 15 k - 25 )}{24 k ^{2} - 40 k} : 5

= 5

- \frac{7}{2} \div 3

\frac{x ^{2} - 10 x + 25}{x - 5}

4 \frac{1}{2} + 4^{2} + 3^{2}

\frac{5 x ^{4} - 9 x ^{3} - 23 x ^{2} + 36 x + 12}{x ^{2} - 4}

1 2^{8}

What is (\frac{8k)/(24k^2-40k)}{1/(15k-25)} ?
The solution to (\frac{8k)/(24k^2-40k)}{1/(15k-25)} is 5