What is (12z^{-6})/(4(b^{-4)z^{-4})^{-2}} ?

The solution to (12z^{-6})/(4(b^{-4)z^{-4})^{-2}} is 3/(z^{14)b^8}

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simplify (12z^{-6})/(4(b^{-4)z^{-4})^{-2}}

simplify

\frac{12 z ^{- 6}}{4 ( b ^{- 4} z ^{- 4} ) ^{- 2}}

\frac{3}{z ^{14} b ^{8}}

Solution steps

\frac{12 z ^{- 6}}{4 ( b ^{- 4} z ^{- 4} ) ^{- 2}}

Factor the number:

12 = 4 \cdot 3

= \frac{4 \cdot 3 z ^{- 6}}{4 ( b ^{- 4} z ^{- 4} ) ^{- 2}}

Cancel the common factor:

4

= \frac{3 z ^{- 6}}{( b ^{- 4} z ^{- 4} ) ^{- 2}}

Simplify

\frac{3 z ^{- 6}}{( b ^{- 4} z ^{- 4} ) ^{- 2}} : \frac{3}{z ^{14} b ^{8}}

= \frac{3}{z ^{14} b ^{8}}

(3 x - 12 y) + (4 x - 8 y)

5 c^{3} \cdot c^{6}

(5 x^{2} - 3 x) (8 x^{2} + 4 x)

\frac{5 80}{32}

(4 q^{4} + 3 q^{2} + 8 q) + (5 q^{3} - 2 q^{2} - q)

What is (12z^{-6})/(4(b^{-4)z^{-4})^{-2}} ?
The solution to (12z^{-6})/(4(b^{-4)z^{-4})^{-2}} is 3/(z^{14)b^8}