What is sqrt(2^{-1)+3^{-1}+4^{-1}} ?

The solution to sqrt(2^{-1)+3^{-1}+4^{-1}} is (sqrt(13))/(2sqrt(3))

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simplify sqrt(2^{-1)+3^{-1}+4^{-1}}

simplify

2^{- 1} + 3^{- 1} + 4^{- 1}

\frac{13}{2 3}

Decimal Notation

1.04083 \dots

Solution steps

2^{- 1} + 3^{- 1} + 4^{- 1}

Simplify

2^{- 1} + 3^{- 1} + 4^{- 1} : \frac{13}{12}

= \frac{13}{12}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= \frac{13}{12}

12 = 23

= \frac{13}{2 3}

r^{2} \cdot r

3 x \cdot 5

A - (A - B)

72 \cdot 5

\frac{m ^{2} - 3 m + 2}{m ^{2} - m}

What is sqrt(2^{-1)+3^{-1}+4^{-1}} ?
The solution to sqrt(2^{-1)+3^{-1}+4^{-1}} is (sqrt(13))/(2sqrt(3))