What is ((1-3i)*(3-i))/(-2-2i) ?

The solution to ((1-3i)*(3-i))/(-2-2i) is 5/2+5/2 i

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simplify ((1-3i)*(3-i))/(-2-2i)

simplify

\frac{( 1 - 3 i ) \cdot ( 3 - i )}{- 2 - 2 i}

\frac{5}{2} + \frac{5}{2} i

Solution steps

\frac{( 1 - 3 i ) ( 3 - i )}{- 2 - 2 i}

Multiply by the conjugate

\frac{- 2 + 2 i}{- 2 + 2 i}

= \frac{( 1 - 3 i ) ( 3 - i ) ( - 2 + 2 i )}{( - 2 - 2 i ) ( - 2 + 2 i )}

Simplify

\frac{( 1 - 3 i ) ( 3 - i ) ( - 2 + 2 i )}{( - 2 - 2 i ) ( - 2 + 2 i )} : \frac{20 + 20 i}{8}

= \frac{20 + 20 i}{8}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{20}{8} + \frac{20}{8} i

Simplify

\frac{20}{8} + \frac{20}{8} i : \frac{5}{2} + \frac{5}{2} i

= \frac{5}{2} + \frac{5}{2} i

\frac{4 ^{\frac{3}{2}}}{\frac{3}{2}}

5 - 15

(8 x^{\frac{- 2}{3}}) x^{\frac{1}{6}}

\frac{1}{3} 3

\frac{( 2 + \frac{2}{5} )}{( \frac{18}{5} )} - \frac{\frac{7}{9}}{\frac{4}{3}}

What is ((1-3i)*(3-i))/(-2-2i) ?
The solution to ((1-3i)*(3-i))/(-2-2i) is 5/2+5/2 i