What is log_{10}(a/(b^2)) ?

The solution to log_{10}(a/(b^2)) is log_{10}(a)-2log_{10}(b)

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simplify log_{10}(a/(b^2))

simplify

lo g_{10} (\frac{a}{b ^{2}})

lo g_{10} (a) - 2 lo g_{10} (b)

Solution steps

lo g_{10} (\frac{a}{b ^{2}})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{a}{b ^{2}}) = lo g_{10} (a) - lo g_{10} (b^{2})

= lo g_{10} (a) - lo g_{10} (b^{2})

Simplify

lo g_{10} (b^{2}) : 2 lo g_{10} (b)

= lo g_{10} (a) - 2 lo g_{10} (b)

2 - 22

(6 y^{2} + 5 y^{4}) 2

sec (x) tan^{2} (x) + sec (x)

23 + 2 i

(- 73) (1110)

What is log_{10}(a/(b^2)) ?
The solution to log_{10}(a/(b^2)) is log_{10}(a)-2log_{10}(b)