What is (x^3+3x^2)/(x^2-9) ?

The solution to (x^3+3x^2)/(x^2-9) is (x^2)/(x-3)

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simplify (x^3+3x^2)/(x^2-9)

simplify

\frac{x ^{3} + 3 x ^{2}}{x ^{2} - 9}

\frac{x ^{2}}{x - 3}

Solution steps

\frac{x ^{3} + 3 x ^{2}}{x ^{2} - 9}

Factor

x^{3} + 3 x^{2} : x^{2} (x + 3)

= \frac{x ^{2} ( x + 3 )}{x ^{2} - 9}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{x ^{2} ( x + 3 )}{( x + 3 ) ( x - 3 )}

Cancel the common factor:

x + 3

= \frac{x ^{2}}{x - 3}

2 x^{2} (3 x + 5 x^{2})

(2 - 7) (1 + 27)

(- 1 + h)^{2} + 4 (- 1 + h) - (- 3)

1 - \frac{19}{20}

x y^{4} + x^{4} y^{5}