What is (x^{-2}y^{-4}z^3)^{-2} ?

The solution to (x^{-2}y^{-4}z^3)^{-2} is (x^4y^8)/(z^6)

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simplify (x^{-2}y^{-4}z^3)^{-2}

simplify

(x^{- 2} y^{- 4} z^{3})^{- 2}

\frac{x ^{4} y ^{8}}{z ^{6}}

Solution steps

(x^{- 2} y^{- 4} z^{3})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(x^{- 2} y^{- 4} z^{3})^{- 2} = \frac{1}{( x ^{- 2} y ^{- 4} z ^{3} ) ^{2}}

= \frac{1}{( x ^{- 2} y ^{- 4} z ^{3} ) ^{2}}

Simplify

(x^{- 2} y^{- 4} z^{3})^{2} : \frac{z ^{6}}{x ^{4} y ^{8}}

= \frac{1}{\frac{z ^{6}}{x ^{4} y ^{8}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{4} y ^{8}}{z ^{6}}

(5 x^{3} - x^{2} + 2 x) + (2 x^{3} - 3 x^{2} + 2 x)

(- 2 x^{6})^{4} \cdot (\frac{1}{4} x)^{2}

\frac{8}{11}

x^{3} - 4 x^{2} - 21 x

What is (x^{-2}y^{-4}z^3)^{-2} ?
The solution to (x^{-2}y^{-4}z^3)^{-2} is (x^4y^8)/(z^6)