What is (-2x^3+4x)/(-6x+1/x)(-1) ?

The solution to (-2x^3+4x)/(-6x+1/x)(-1) is -((-2x^3+4x)x)/(-6x^2+1)

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simplify (-2x^3+4x)/(-6x+1/x)(-1)

simplify

\frac{- 2 x ^{3} + 4 x}{- 6 x + \frac{1}{x}} (- 1)

- \frac{( - 2 x ^{3} + 4 x ) x}{- 6 x ^{2} + 1}

Solution steps

\frac{- 2 x ^{3} + 4 x}{- 6 x + \frac{1}{x}} (- 1)

Join

- 6 x + \frac{1}{x} : \frac{- 6 x ^{2} + 1}{x}

= \frac{- 2 x ^{3} + 4 x}{\frac{- 6 x ^{2} + 1}{x}} (- 1)

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

\frac{- 2 x ^{3} + 4 x}{\frac{- 6 x ^{2} + 1}{x}} = \frac{( - 2 x ^{3} + 4 x ) x}{- 6 x ^{2} + 1}

= \frac{( - 2 x ^{3} + 4 x ) x}{- 6 x ^{2} + 1} (- 1)

Apply rule:

a (- b) = - ab

\frac{( - 2 x ^{3} + 4 x ) x}{- 6 x ^{2} + 1} (- 1) = - \frac{( - 2 x ^{3} + 4 x ) x}{- 6 x ^{2} + 1} \cdot 1

= - \frac{( - 2 x ^{3} + 4 x ) x}{- 6 x ^{2} + 1} \cdot 1

Apply rule:

a \cdot 1 = a

= - \frac{( - 2 x ^{3} + 4 x ) x}{- 6 x ^{2} + 1}

\frac{1}{5} \cdot \frac{4}{5}

2 x^{2} + 2 x - 6

\frac{4 x ^{3} y ^{5}}{12 x ^{4} y ^{3}}

12 8^{4}

\frac{7}{6} + \frac{13}{10}

What is (-2x^3+4x)/(-6x+1/x)(-1) ?
The solution to (-2x^3+4x)/(-6x+1/x)(-1) is -((-2x^3+4x)x)/(-6x^2+1)