What is (7y-14)/(y^2-7y+10)+(10)/(y-5) ?

The solution to (7y-14)/(y^2-7y+10)+(10)/(y-5) is (17)/(y-5)

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simplify (7y-14)/(y^2-7y+10)+(10)/(y-5)

simplify

\frac{7 y - 14}{y ^{2} - 7 y + 10} + \frac{10}{y - 5}

\frac{17}{y - 5}

Solution steps

\frac{7 y - 14}{y ^{2} - 7 y + 10} + \frac{10}{y - 5}

Cancel

\frac{7 y - 14}{y ^{2} - 7 y + 10} : \frac{7}{y - 5}

= \frac{7}{y - 5} + \frac{10}{y - 5}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{7 + 10}{y - 5}

Add the numbers:

7 + 10 = 17

= \frac{17}{y - 5}

4 k^{2} (- 3 k^{2} - 4 k + 5)

\frac{7}{x} - \frac{5}{y}

3 \cdot 1 \frac{1}{2}

1 \frac{2}{7}

What is (7y-14)/(y^2-7y+10)+(10)/(y-5) ?
The solution to (7y-14)/(y^2-7y+10)+(10)/(y-5) is (17)/(y-5)