What is sqrt((sin^4(3t))/(16t^2)) ?

The solution to sqrt((sin^4(3t))/(16t^2)) is (sin^2(3t))/(4t)

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simplify sqrt((sin^4(3t))/(16t^2))

simplify

\frac{sin ^{4} ( 3 t )}{16 t ^{2}}

\frac{sin ^{2} ( 3 t )}{4 t}

Solution steps

\frac{sin ^{4} ( 3 t )}{16 t ^{2}}

Apply radical rule:

\frac{a}{b} = \frac{a}{b},

assuming

a \geq 0, b \geq 0

= \frac{sin ^{4} ( 3 t )}{16 t ^{2}}

Simplify

sin^{4} (3 t) : sin^{2} (3 t)

= \frac{sin ^{2} ( 3 t )}{16 t ^{2}}

Simplify

16 t^{2} : 4 t

= \frac{sin ^{2} ( 3 t )}{4 t}

6 \div \frac{10}{7}

\frac{\frac{x}{x + 1} - \frac{1}{x}}{\frac{x}{x + 1} + \frac{1}{x}}

\frac{2 x ^{2} - x - 1}{x - 1}

\frac{sin ^{2} ( y )}{1 - cos ( y )}

\frac{2 a}{2}

What is sqrt((sin^4(3t))/(16t^2)) ?
The solution to sqrt((sin^4(3t))/(16t^2)) is (sin^2(3t))/(4t)