What is i(6-5i)-2(4-3i) ?

The solution to i(6-5i)-2(4-3i) is -3+12i

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simplify i(6-5i)-2(4-3i)

simplify

i (6 - 5 i) - 2 (4 - 3 i)

- 3 + 12 i

Solution steps

i (6 - 5 i) - 2 (4 - 3 i)

Expand

i (6 - 5 i) : 6 i + 5

= 6 i + 5 - 2 (4 - 3 i)

Expand

- 2 (4 - 3 i) : - 8 + 6 i

= 6 i + 5 - 8 + 6 i

Group like terms

= 6 i + 6 i + 5 - 8

Add similar elements:

6 i + 6 i = 12 i

= 12 i + 5 - 8

Subtract the numbers:

5 - 8 = - 3

= 12 i - 3

Rewrite in standard complex form:

- 3 + 12 i

= - 3 + 12 i

(2 - 6 i) (- 4 + 3 i)

262144

2.3 \cdot 1 0^{6}

cos (a) cos (b) - sin (a) sin (b)

\frac{7}{2 + 3}