What is (2x^2-7x-4)/(x^2-5x+4) ?

The solution to (2x^2-7x-4)/(x^2-5x+4) is (2x+1)/(x-1)

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simplify (2x^2-7x-4)/(x^2-5x+4)

simplify

\frac{2 x ^{2} - 7 x - 4}{x ^{2} - 5 x + 4}

\frac{2 x + 1}{x - 1}

Solution steps

\frac{2 x ^{2} - 7 x - 4}{x ^{2} - 5 x + 4}

Factor

2 x^{2} - 7 x - 4 : (2 x + 1) (x - 4)

= \frac{( 2 x + 1 ) ( x - 4 )}{x ^{2} - 5 x + 4}

Factor

x^{2} - 5 x + 4 : (x - 1) (x - 4)

= \frac{( 2 x + 1 ) ( x - 4 )}{( x - 1 ) ( x - 4 )}

Cancel the common factor:

x - 4

= \frac{2 x + 1}{x - 1}

cos^{2} (x) + cos (x)

0.5 \cdot \frac{2}{3}

\frac{x ^{2} + 3 x - 4}{x ^{2} - 8 x + 7}

\frac{360}{60}

\frac{x ^{3} - 2 x + x}{x ^{3} - x}

What is (2x^2-7x-4)/(x^2-5x+4) ?
The solution to (2x^2-7x-4)/(x^2-5x+4) is (2x+1)/(x-1)