What is (21x^4-14x^3-28x^2)/(7x^2) ?

The solution to (21x^4-14x^3-28x^2)/(7x^2) is 3x^2-2x-4

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simplify (21x^4-14x^3-28x^2)/(7x^2)

simplify

\frac{21 x ^{4} - 14 x ^{3} - 28 x ^{2}}{7 x ^{2}}

3 x^{2} - 2 x - 4

Solution steps

\frac{21 x ^{4} - 14 x ^{3} - 28 x ^{2}}{7 x ^{2}}

Factor

21 x^{4} - 14 x^{3} - 28 x^{2} : 7 x^{2} (3 x^{2} - 2 x - 4)

= \frac{7 x ^{2} ( 3 x ^{2} - 2 x - 4 )}{7 x ^{2}}

Cancel the common factor:

7

= \frac{x ^{2} ( 3 x ^{2} - 2 x - 4 )}{x ^{2}}

Cancel the common factor:

x^{2}

= 3 x^{2} - 2 x - 4

4 x - 3 x^{2}

490 y^{5} w^{6}

\frac{5}{6} \cdot \frac{4}{15} - \frac{3}{5} \cdot \frac{20}{18}

(2 n + 3)^{3}

\frac{25}{25}

What is (21x^4-14x^3-28x^2)/(7x^2) ?
The solution to (21x^4-14x^3-28x^2)/(7x^2) is 3x^2-2x-4