What is (2x+3)^2+(2x-3)^2 ?

The solution to (2x+3)^2+(2x-3)^2 is 8x^2+18

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simplify (2x+3)^2+(2x-3)^2

simplify

(2 x + 3)^{2} + (2 x - 3)^{2}

8 x^{2} + 18

Solution steps

(2 x + 3)^{2} + (2 x - 3)^{2}

Expand

(2 x + 3)^{2} : 4 x^{2} + 12 x + 9

= 4 x^{2} + 12 x + 9 + (2 x - 3)^{2}

Expand

(2 x - 3)^{2} : 4 x^{2} - 12 x + 9

= 4 x^{2} + 12 x + 9 + 4 x^{2} - 12 x + 9

Group like terms

= 4 x^{2} + 4 x^{2} + 12 x - 12 x + 9 + 9

Add similar elements:

4 x^{2} + 4 x^{2} = 8 x^{2}

= 8 x^{2} + 12 x - 12 x + 9 + 9

Add similar elements:

12 x - 12 x = 0

= 8 x^{2} + 9 + 9

Add the numbers:

9 + 9 = 18

= 8 x^{2} + 18

\frac{52}{65}

\frac{c ^{2} - d ^{2}}{d ^{2} + c d - 2 c ^{2}}

\frac{1 + x - y}{1 + x + y} + \frac{1 + x + y}{1 + x - y}

\frac{5}{x} \cdot \frac{2 x}{y ^{2}} \cdot \frac{3 y}{10}

8 + \frac{x - 1}{x + 4}