What is 5(x^{2n-1})^n*(2x^{3n+1})^2 ?

The solution to 5(x^{2n-1})^n*(2x^{3n+1})^2 is 5x^{(2n-1)n}(2x^{3n+1})^2

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simplify 5(x^{2n-1})^n*(2x^{3n+1})^2

simplify

5 (x^{2 n - 1})^{n} \cdot (2 x^{3 n + 1})^{2}

5 x^{(2 n - 1) n} (2 x^{3 n + 1})^{2}

Solution steps

5 (x^{2 n - 1})^{n} (2 x^{3 n + 1})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

(x^{2 n - 1})^{n} = x^{(2 n - 1) n}

= 5 x^{(2 n - 1) n} (2 x^{3 n + 1})^{2}

\frac{3}{4 x ^{2}} + \frac{x}{x ^{2} - 7}

w^{2} - 2 w + 1

16384

- (- \frac{1}{2})^{2}

\frac{( \frac{T}{p \cdot n ^{2} \cdot D ^{4}} )}{( \frac{x}{p \cdot n ^{3} \cdot D ^{5}} )}

What is 5(x^{2n-1})^n*(2x^{3n+1})^2 ?
The solution to 5(x^{2n-1})^n*(2x^{3n+1})^2 is 5x^{(2n-1)n}(2x^{3n+1})^2