What is 1/(s^2+s+1+\frac{1){s+1}} ?

The solution to 1/(s^2+s+1+\frac{1){s+1}} is (s+1)/(s^3+2s^2+2s+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 1/(s^2+s+1+\frac{1){s+1}}

simplify

\frac{1}{s ^{2} + s + 1 + \frac{1}{s + 1}}

\frac{s + 1}{s ^{3} + 2 s ^{2} + 2 s + 2}

Solution steps

\frac{1}{s ^{2} + s + 1 + \frac{1}{s + 1}}

Join

s^{2} + s + 1 + \frac{1}{s + 1} : \frac{s ^{3} + 2 s ^{2} + 2 s + 2}{s + 1}

= \frac{1}{\frac{s ^{3} + 2 s ^{2} + 2 s + 2}{s + 1}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{s + 1}{s ^{3} + 2 s ^{2} + 2 s + 2}

(6^{3})^{\frac{1}{4}}

\frac{36}{39}

0 \cdot (- 3)

\frac{36}{63}

\frac{36}{99}

What is 1/(s^2+s+1+\frac{1){s+1}} ?
The solution to 1/(s^2+s+1+\frac{1){s+1}} is (s+1)/(s^3+2s^2+2s+2)