What are the solutions to the equation m^2+5m-14=0 ?

The solutions to the equation m^2+5m-14=0 are m=2,m=-7

Find the zeros of m^2+5m-14=0

The zeros of m^2+5m-14=0 are m=2,m=-7

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m^{2} + 5 m - 14 = 0

m = 2, m = - 7

Solution steps

m^{2} + 5 m - 14 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

m_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 5 + 9}{2 \cdot 1}, m_{2} = \frac{- 5 - 9}{2 \cdot 1}

m = \frac{- 5 + 9}{2 \cdot 1} : 2

m = \frac{- 5 - 9}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

m = 2, m = - 7

∣ x - 5 ∣ > 7

2 (2 y + 9) = 50

7 r^{2} + 5 r + 9 = 0

8 t^{2} - 64 + 281

What are the solutions to the equation m^2+5m-14=0 ?
The solutions to the equation m^2+5m-14=0 are m=2,m=-7
Find the zeros of m^2+5m-14=0
The zeros of m^2+5m-14=0 are m=2,m=-7