What is (9x^4y^3)/(27x^2y^2) ?

The solution to (9x^4y^3)/(27x^2y^2) is (x^2y)/3

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simplify (9x^4y^3)/(27x^2y^2)

simplify

\frac{9 x ^{4} y ^{3}}{27 x ^{2} y ^{2}}

\frac{x ^{2} y}{3}

Solution steps

\frac{9 x ^{4} y ^{3}}{27 x ^{2} y ^{2}}

Factor the number:

27 = 9 \cdot 3

= \frac{9 x ^{4} y ^{3}}{9 \cdot 3 x ^{2} y ^{2}}

Cancel the common factor:

9

= \frac{x ^{4} y ^{3}}{3 x ^{2} y ^{2}}

Simplify

\frac{x ^{4}}{x ^{2}} : x^{2}

= \frac{x ^{2} y ^{3}}{3 y ^{2}}

Simplify

\frac{y ^{3}}{y ^{2}} : y

= \frac{x ^{2} y}{3}

1 - i^{2}

\frac{3}{2 x} - \frac{3 x}{2 ( x ^{2} - 4 x + 4 )}

\frac{cos ( x ) sec ( x )}{tan ( x )}

1 0^{- 100}