What is ((x^6y^3)^{(-1)/3})/((x^4y^2)^{(-1)/2)} ?

The solution to ((x^6y^3)^{(-1)/3})/((x^4y^2)^{(-1)/2)} is 1

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simplify ((x^6y^3)^{(-1)/3})/((x^4y^2)^{(-1)/2)}

simplify

\frac{( x ^{6} y ^{3} ) ^{\frac{- 1}{3}}}{( x ^{4} y ^{2} ) ^{\frac{- 1}{2}}}

1

Solution steps

\frac{( x ^{6} y ^{3} ) ^{\frac{- 1}{3}}}{( x ^{4} y ^{2} ) ^{\frac{- 1}{2}}}

Simplify

(x^{6} y^{3})^{\frac{- 1}{3}} : \frac{1}{x ^{2}} \cdot \frac{1}{y}

= \frac{\frac{1}{x ^{2}} \cdot \frac{1}{y}}{( x ^{4} y ^{2} ) ^{\frac{- 1}{2}}}

Simplify

(x^{4} y^{2})^{\frac{- 1}{2}} : \frac{1}{x ^{2}} \cdot \frac{1}{y}

= \frac{\frac{1}{x ^{2}} \cdot \frac{1}{y}}{\frac{1}{x ^{2}} \cdot \frac{1}{y}}

Cancel the common factor:

\frac{1}{x ^{2}}

= \frac{\frac{1}{y}}{\frac{1}{y}}

Apply the fraction rule:

\frac{a}{a} = 1

= 1

\frac{2}{x + 1} - \frac{2 x}{x - 1}

(2 x - 3) - (x - 6)

\frac{12 x ^{2}}{6 x ^{4} + 12 x ^{3}}

\frac{125}{5}

1.5625

What is ((x^6y^3)^{(-1)/3})/((x^4y^2)^{(-1)/2)} ?
The solution to ((x^6y^3)^{(-1)/3})/((x^4y^2)^{(-1)/2)} is 1