What are the solutions to the equation 64x^2-80x+25=0 ?

The solutions to the equation 64x^2-80x+25=0 are x= 5/8

Find the zeros of 64x^2-80x+25=0

The zeros of 64x^2-80x+25=0 are x= 5/8

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64 x^{2} - 80 x + 25 = 0

x = \frac{5}{8}

Solution steps

64 x^{2} - 80 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 \cdot 64 \cdot 25}{2 \cdot 64}

(- 80)^{2} - 4 \cdot 64 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 80 ) \pm 0}{2 \cdot 64}

x = \frac{- ( - 80 )}{2 \cdot 64}

\frac{- ( - 80 )}{2 \cdot 64} = \frac{5}{8}

x = \frac{5}{8}

The solution to the quadratic equation is:

x = \frac{5}{8}

- 4 ∣ 7 x - 5 ∣ = 8

x^{2} - y^{2}

\frac{1}{- \frac{3}{5}}

(\frac{3 x ^{- 2} y ^{2}}{z ^{4}})^{\frac{1}{4}}

∣ y - 5 ∣ = ∣ y - 4 ∣

What are the solutions to the equation 64x^2-80x+25=0 ?
The solutions to the equation 64x^2-80x+25=0 are x= 5/8
Find the zeros of 64x^2-80x+25=0
The zeros of 64x^2-80x+25=0 are x= 5/8