What is 3(x^2-1)-(x^2-7x+10) ?

The solution to 3(x^2-1)-(x^2-7x+10) is 2x^2+7x-13

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simplify 3(x^2-1)-(x^2-7x+10)

simplify

3 (x^{2} - 1) - (x^{2} - 7 x + 10)

2 x^{2} + 7 x - 13

Solution steps

3 (x^{2} - 1) - (x^{2} - 7 x + 10)

Apply the distributive law:

- (a - b) = - a + b

- (x^{2} - 7 x + 10) = - x^{2} + 7 x - 10

= 3 (x^{2} - 1) - x^{2} + 7 x - 10

Expand

3 (x^{2} - 1) : 3 x^{2} - 3

= 3 x^{2} - 3 - x^{2} + 7 x - 10

Group like terms

= 3 x^{2} - x^{2} + 7 x - 3 - 10

Add similar elements:

3 x^{2} - x^{2} = 2 x^{2}

= 2 x^{2} + 7 x - 3 - 10

Subtract the numbers:

- 3 - 10 = - 13

= 2 x^{2} + 7 x - 13

\frac{- 1}{5} - \frac{3}{8}

30 \cdot \frac{3}{5}

g (f (- 1))

9 m^{2} - 6 mn + n^{2}

(x^{2} + x y + y^{2}) \cdot (x - y)

What is 3(x^2-1)-(x^2-7x+10) ?
The solution to 3(x^2-1)-(x^2-7x+10) is 2x^2+7x-13