What is (2x^3-3x^2+x-6)/((x-2)) ?

The solution to (2x^3-3x^2+x-6)/((x-2)) is 2x^2+x+3

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simplify (2x^3-3x^2+x-6)/((x-2))

simplify

\frac{2 x ^{3} - 3 x ^{2} + x - 6}{( x - 2 )}

2 x^{2} + x + 3

Solution steps

\frac{2 x ^{3} - 3 x ^{2} + x - 6}{x - 2}

Factor

2 x^{3} - 3 x^{2} + x - 6 : (x - 2) (2 x^{2} + x + 3)

= \frac{( x - 2 ) ( 2 x ^{2} + x + 3 )}{x - 2}

Cancel the common factor:

x - 2

= 2 x^{2} + x + 3

\frac{cos ( θ ) + cot ( θ ) sin ( θ )}{cot ( θ )}

\frac{1}{1} - \frac{1}{1}

\frac{75}{5}

(- 7 x^{4} + 6 x^{2} + 6 x + 5) + (- 2 x^{2} + 2 + 3 x^{5})

(6 x^{2})^{3}

What is (2x^3-3x^2+x-6)/((x-2)) ?
The solution to (2x^3-3x^2+x-6)/((x-2)) is 2x^2+x+3