What is log_{10}((7/8)^x) ?

The solution to log_{10}((7/8)^x) is x(log_{10}(7)-3log_{10}(2))

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simplify log_{10}((7/8)^x)

simplify

lo g_{10} ((\frac{7}{8})^{x})

x (lo g_{10} (7) - 3 lo g_{10} (2))

Solution steps

lo g_{10} ((\frac{7}{8})^{x})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x), x > 0

lo g_{10} ((\frac{7}{8})^{x}) = x lo g_{10} (\frac{7}{8})

= x lo g_{10} (\frac{7}{8})

lo g_{10} (\frac{7}{8}) = lo g_{10} (7) - 3 lo g_{10} (2)

= x (lo g_{10} (7) - 3 lo g_{10} (2))

a^{3} + 8 b^{3}

6 9^{2}

1.056 - 2.33 (\frac{0.246}{50})

327 + 48 + 63 + 230

(x + 2) (x - 2) (x + 4) + (x + 4) (4 - x)

What is log_{10}((7/8)^x) ?
The solution to log_{10}((7/8)^x) is x(log_{10}(7)-3log_{10}(2))