What are the solutions to the equation 5x^2+14x-24=0 ?

The solutions to the equation 5x^2+14x-24=0 are x= 6/5 ,x=-4

Find the zeros of 5x^2+14x-24=0

The zeros of 5x^2+14x-24=0 are x= 6/5 ,x=-4

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5 x^{2} + 14 x - 24 = 0

x = \frac{6}{5}, x = - 4

Decimal Notation

x = 1.2, x = - 4

Solution steps

5 x^{2} + 14 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 5 ( - 24 )}{2 \cdot 5}

1 4^{2} - 4 \cdot 5 (- 24) = 26

x_{1, 2} = \frac{- 14 \pm 26}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 14 + 26}{2 \cdot 5}, x_{2} = \frac{- 14 - 26}{2 \cdot 5}

x = \frac{- 14 + 26}{2 \cdot 5} : \frac{6}{5}

x = \frac{- 14 - 26}{2 \cdot 5} : - 4

The solutions to the quadratic equation are:

x = \frac{6}{5}, x = - 4

3 y = 18

2 d^{2} + 13 d + 11

∣ y ∣ \leq 6

\frac{2}{3} x + 6 = \frac{1}{2} x + \frac{1}{4} x

What are the solutions to the equation 5x^2+14x-24=0 ?
The solutions to the equation 5x^2+14x-24=0 are x= 6/5 ,x=-4
Find the zeros of 5x^2+14x-24=0
The zeros of 5x^2+14x-24=0 are x= 6/5 ,x=-4