What is log_{10}(72)-2log_{10}(3)-3log_{10}(2) ?

The solution to log_{10}(72)-2log_{10}(3)-3log_{10}(2) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{10}(72)-2log_{10}(3)-3log_{10}(2)

simplify

lo g_{10} (72) - 2 lo g_{10} (3) - 3 lo g_{10} (2)

0

Solution steps

lo g_{10} (72) - 2 lo g_{10} (3) - 3 lo g_{10} (2)

- 2 lo g_{10} (3) = - lo g_{10} (3^{2})

- 3 lo g_{10} (2) = - lo g_{10} (2^{3})

= lo g_{10} (72) - lo g_{10} (3^{2}) - lo g_{10} (2^{3})

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (72) - lo g_{10} (3^{2}) = lo g_{10} (\frac{72}{3 ^{2}})

= lo g_{10} (\frac{72}{3 ^{2}}) - lo g_{10} (2^{3})

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (\frac{72}{3 ^{2}}) - lo g_{10} (2^{3}) = lo g_{10} (\frac{\frac{72}{3 ^{2}}}{2 ^{3}})

= lo g_{10} (\frac{\frac{72}{3 ^{2}}}{2 ^{3}})

\frac{\frac{72}{3 ^{2}}}{2 ^{3}} = 1

= lo g_{10} (1)

Apply log rule:

lo g_{a} (1) = 0

= 0

(4 \cdot 6 x y^{6})^{4}

500 0^{2}

(\frac{2}{x} - \frac{1}{x ^{3}})^{2}

\frac{5}{x - 1} \cdot \frac{x - 1}{25 ( x - 2 )}

What is log_{10}(72)-2log_{10}(3)-3log_{10}(2) ?
The solution to log_{10}(72)-2log_{10}(3)-3log_{10}(2) is 0