What is factor 1-4/9 a^8 ?

The solution to factor 1-4/9 a^8 is (1+2/3 a^4)(1-2/3 a^4)

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factor 1-4/9 a^8

factor

1 - \frac{4}{9} a^{8}

(1 + \frac{2}{3} a^{4}) (1 - \frac{2}{3} a^{4})

Solution steps

1 - \frac{4}{9} a^{8}

1 = 1^{2}

\frac{4}{9} a^{8} = (\frac{2}{3} a^{4})^{2}

= 1^{2} - (\frac{2}{3} a^{4})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

1^{2} - (\frac{2}{3} a^{4})^{2} = (1 + \frac{2}{3} a^{4}) (1 - \frac{2}{3} a^{4})

= (1 + \frac{2}{3} a^{4}) (1 - \frac{2}{3} a^{4})

(2 x - 5 y + 3 z) (- 3 y - 6 z + x)

45 0^{2}

lo g_{2} (162)

5 x - 9 - 2 - 3 x

\frac{3 t ^{- 1}}{- 3 ( t ^{- 1} ) ^{4}}

What is factor 1-4/9 a^8 ?
The solution to factor 1-4/9 a^8 is (1+2/3 a^4)(1-2/3 a^4)