What are the solutions to the equation 3x^2+5x-3=0 ?

The solutions to the equation 3x^2+5x-3=0 are x=(-5+sqrt(61))/6 ,x=(-5-sqrt(61))/6

Find the zeros of 3x^2+5x-3=0

The zeros of 3x^2+5x-3=0 are x=(-5+sqrt(61))/6 ,x=(-5-sqrt(61))/6

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3 x^{2} + 5 x - 3 = 0

x = \frac{- 5 + 61}{6}, x = \frac{- 5 - 61}{6}

Decimal Notation

x = 0.46837 \dots, x = - 2.13504 \dots

Solution steps

3 x^{2} + 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 3) = 61

x_{1, 2} = \frac{- 5 \pm 61}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 61}{2 \cdot 3}, x_{2} = \frac{- 5 - 61}{2 \cdot 3}

x = \frac{- 5 + 61}{2 \cdot 3} : \frac{- 5 + 61}{6}

x = \frac{- 5 - 61}{2 \cdot 3} : \frac{- 5 - 61}{6}

The solutions to the quadratic equation are:

x = \frac{- 5 + 61}{6}, x = \frac{- 5 - 61}{6}

3 (x - 2) - 2 x + 3 = - 12

\frac{\frac{π}{2}}{6}

(\frac{1}{7})^{2}

(34 3^{- \frac{1}{4}})^{- \frac{4}{3}}

f = 1 + 1

What are the solutions to the equation 3x^2+5x-3=0 ?
The solutions to the equation 3x^2+5x-3=0 are x=(-5+sqrt(61))/6 ,x=(-5-sqrt(61))/6
Find the zeros of 3x^2+5x-3=0
The zeros of 3x^2+5x-3=0 are x=(-5+sqrt(61))/6 ,x=(-5-sqrt(61))/6