What is (6x-18)/(x^2-4)*(x^2+5x+6)/(x^2-9) ?

The solution to (6x-18)/(x^2-4)*(x^2+5x+6)/(x^2-9) is 6/(x-2)

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simplify (6x-18)/(x^2-4)*(x^2+5x+6)/(x^2-9)

simplify

\frac{6 x - 18}{x ^{2} - 4} \cdot \frac{x ^{2} + 5 x + 6}{x ^{2} - 9}

\frac{6}{x - 2}

Solution steps

\frac{6 x - 18}{x ^{2} - 4} \cdot \frac{x ^{2} + 5 x + 6}{x ^{2} - 9}

Cancel

\frac{x ^{2} + 5 x + 6}{x ^{2} - 9} : \frac{x + 2}{x - 3}

= \frac{6 x - 18}{x ^{2} - 4} \cdot \frac{x + 2}{x - 3}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 6 x - 18 ) ( x + 2 )}{( x ^{2} - 4 ) ( x - 3 )}

Factor

6 x - 18 : 6 (x - 3)

= \frac{6 ( x - 3 ) ( x + 2 )}{( x ^{2} - 4 ) ( x - 3 )}

Cancel the common factor:

x - 3

= \frac{6 ( x + 2 )}{x ^{2} - 4}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{6 ( x + 2 )}{( x + 2 ) ( x - 2 )}

Cancel the common factor:

x + 2

= \frac{6}{x - 2}

- 5 + \frac{1}{3}

(3 x^{2} - 5) (3 x^{2} + 5) - x^{2} (3 x - 1)^{2}

\frac{x ^{2}}{2} + x

5 h^{2} - 25

3 \cdot + 9

What is (6x-18)/(x^2-4)*(x^2+5x+6)/(x^2-9) ?
The solution to (6x-18)/(x^2-4)*(x^2+5x+6)/(x^2-9) is 6/(x-2)