What is (x^2-9x+18)/(x^2-4x-12) ?

The solution to (x^2-9x+18)/(x^2-4x-12) is (x-3)/(x+2)

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simplify (x^2-9x+18)/(x^2-4x-12)

simplify

\frac{x ^{2} - 9 x + 18}{x ^{2} - 4 x - 12}

\frac{x - 3}{x + 2}

Solution steps

\frac{x ^{2} - 9 x + 18}{x ^{2} - 4 x - 12}

Factor

x^{2} - 9 x + 18 : (x - 3) (x - 6)

= \frac{( x - 3 ) ( x - 6 )}{x ^{2} - 4 x - 12}

Factor

x^{2} - 4 x - 12 : (x + 2) (x - 6)

= \frac{( x - 3 ) ( x - 6 )}{( x + 2 ) ( x - 6 )}

Cancel the common factor:

x - 6

= \frac{x - 3}{x + 2}

\frac{1 - sin ( θ )}{cos ( θ )}

\frac{\frac{2}{3}}{5}

\frac{2}{3} + \frac{3}{7}

(\frac{3 ^{500}}{9 ^{250}})^{7000}

(- 4 - x^{2})^{2}

What is (x^2-9x+18)/(x^2-4x-12) ?
The solution to (x^2-9x+18)/(x^2-4x-12) is (x-3)/(x+2)